| 1. The action potential (AP) on neuron A will split into four smaller action potentials prior to reaching neuron C.
2. Even if the neurotransmitters secreted by neuron A are excitatory (EPSPs) - there will NOT be enough EPSPs to produce an action potential on neuron C. (Note: there is only one action potential on neuron A - also, for this question, pretend that neuron B does NOT exist.)
3. It is possible that neuron A secretes inhibitory neurotransmitters (NTSs) and neurons B secretes excitatory neurotransmitters.
4. When the action potential on neuron A reaches the axon terminals (butons) and neurotransmitters are released and "hit" neuron C, there will be a change in the Resting Membrane Potential (RMP) of neuron C.
5. There is one action potential on both neuron A and neuron B - IF both neurons secrete neurotransmitters that are inhibitory (IPSPs) and if they reach neuron C at approximately the same time, then an action potential will definitely be formed on neuron C. | 6. IF neuron A secretes dopamine, then we know that neuron C must secrete acetyl choline (ACh).
7. One "hit" from an inhibitory neurotransmitter will cause a neuron's membrane potential to move farther away from the threshold.
8. One "hit" from an excitatory neurotransmitter will cause a neuron's membrane potential to move closwer to the threshold.
9. IF neuron A secreted excitatory NTSs, and IF there were 4 APs (as opposed to the one you
see in the picture) THEN, an action potential could be formed on neuron C. (Would the RMP move enough to reach the threshold?)
10. All action potentials are "membrane events."
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